X+10=4x^2

Solution for X+10=4x^2 equation:

X+10=4X^2

We move all terms to the left:

X+10-(4X^2)=0

determiningTheFunctionDomain
-4X^2+X+10=0

a = -4; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-4)·10
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*-4}=\frac{-1-\sqrt{161}}{-8}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*-4}=\frac{-1+\sqrt{161}}{-8}
$